What are the final products when a diploid onion cell, containing 16 chromosomes undergoes meiosis?
What are the final products when a diploid onion cell, containing 16 chromosomes undergoes
meiosis?
A. 4 cells, each with 8 chromosomes
B. 2 cells, each with 8 chromosomes
C. 4 cells, each with 4 chromosomes
D. 2 cells, each with 16 chromosomes
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2 comments a “What are the final products when a diploid onion cell, containing 16 chromosomes undergoes meiosis?”
A. Meiosis first divides a cell into two cells identical to the original, and then divides them again, but this time giving only half to each cell. The result is four cells, each with half of the original chromosome number.
A. During Meiosis I, the cell replicates all of its DNA (32 chromosomes), just to divide it, resulting in two daughter cells with 16 chromosomes each. During Meiosis II, each of the two cell divides again, but doesn’t replicate it’s DNA, resulting in four cells with 8 chromosomes each.
The answer which said that Meiosis first divides the cell into two daughter cells identical to the parent cell is slightly off. That would be mitosis. In Meiosis I, each daughter cell receives BOTH copies of ONE member of the homologous pair. Ideally, you would have two chromosomes per set in your body, one from your mom, and one from your dad (discounting crossing over). During S phase, the cell would develop two copies of the mommy chromosome and two copies of the daddy chromosome. During Meiosis I, one daughter cell gets both copies of the mommy chromosome and the other daughter cell gets both copies of the daddy chromosome. Since the chromosomes from mommy and daddy are different, and since crossing over might occur between them, and since the daughter cells only one of each homologous pair, the daughter cells cannot be identical to the parent cells or to each other.
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